How to Print Employee Names in Sorted Order Using Java 8

Learn how to print employee names in sorted order using Java 8 Stream API with a simple example. Understand filter(), map(), sorted(), and collect() step by step.

Code Explanation (Step-by-Step) :

First, create an Employee class with id, name, and salary fields.
Next, create a list of Employee objects.
Then, convert the list into a stream using the stream() method.
Use the filter() method to find employees whose salary is greater than 1000.
After that, use the map() method to extract employee names with e -> e.getName().
Then, use the sorted() method to sort the employee names in ascending order.
Finally, use the collect() method to collect the sorted names into a list and print the result.

				
					public class Employee {
	private Integer id;
	private String name;
	private Integer salary;
	
	public Employee(Integer id, String name, Integer salary) {
		super();
		this.id = id;
		this.name = name;
		this.salary = salary;
	}
	public Integer getId() {
		return id;
	}
	public void setId(Integer id) {
		this.id = id;
	}
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public Integer getSalary() {
		return salary;
	}
	public void setSalary(Integer salary) {
		this.salary = salary;
	}
}

				
					import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

public class EmployeeTest {
	public static void main(String[] args) {
		List<Employee> emp = Arrays.asList(
		                     new Employee(1, "anup", 120), 
		                     new Employee(2, "pankaj", 1300),
				             new Employee(3, "vijay", 7230), 
				             new Employee(4, "ravi", 678), 
				             new Employee(5, "aman", 8230));

		List<String> name = emp.stream().filter(r -> r.getSalary() > 1000)
		                   .map(e -> e.getName()).sorted()
				           .collect(Collectors.toList());
		System.out.println("Employee name in sorted order :- " + name);
	}
}

Output :-
Employee name in sorted order :- [aman, pankaj, vijay]

Print Employee Names in Unsorted Order Using Java 8

				
					import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

public class EmployeeTest {
	public static void main(String[] args) {
		List<Employee> emp = Arrays.asList(
		                     new Employee(1, "anup", 120),
		                     new Employee(2, "pankaj", 1300),
				             new Employee(3, "vijay", 7230),
				             new Employee(4, "ravi", 678),
				             new Employee(5, "aman", 8230));

		List<String> name = emp.stream().filter(r -> r.getSalary() > 1000)
		                   .map(Employee::getName)
				           .collect(Collectors.toList());
		System.out.println("Employee name in Unsorted order :- " + name);
	}
}

Output :
Employee Names in Unsorted Order: [pankaj, vijay, aman]

FAQ:

How do you sort employee names in Java 8?
You can sort employee names in Java 8 by using Stream API with map(Employee::getName) and sorted().
What does sorted() do in Java 8 Stream?
The sorted() method sorts stream elements in natural ascending order.
Why use map() in Java 8 Stream?
The map() method transforms each object into another value, such as converting an Employee object into an employee name.
How does filter() work in Java 8 Stream?

Print Employee Names in Unsorted Order Using Java 8

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