Java Program to Find Sum of Digits of a Number

Learn how to find sum of digits of a number in Java. Here we will calculate the sum of digits of a given number using a while loop.

Code Explanation (Step-by-Step)

  • Create an object of the Scanner class using System.in to receive user input.
  • The sc.nextInt() method reads the entered value as an integer and store in num variables.
  • Declare a variable sum and initialize it to 0 to store the sum of digits.
  • Use a while loop to continue processing until the number becomes 0.
  • Find the last digit using the modulo (%) operator.
  • Add the extracted digit to the sum variable.
  • Divide the number by 10 using the division (/) operator to remove the last digit.
  • Repeat the process until all digits have been processed.
  • Now print the sum of the digits.
				
					import java.util.Scanner;

public class SumOfNumber {
    public static void main(String[] args) {
        System.out.println("Enter the digit number:");
        
        Scanner sc = new Scanner(System.in);
        int num = sc.nextInt();
        int digit = 0;
        int sum = 0;

        while (num != 0) {
            digit = num % 10;
            sum = sum + digit;
            num = num / 10;
        }

        sc.close();
        System.out.println("Sum of digit is - " + sum);
    }
}

output :-
Enter the digit number: 257
sum of digit is – 14

Remove Last Digit Using Division

The division (/) operator is used to remove the last digit from the number. When an integer is divided by 10, the fractional part is discarded, leaving only the remaining digits.

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